Why do transition metals form colored compounds?
Most of the compounds of
transition metals are colored in the solid or in the solution states. In the
case of free metal ion, all the five d-orbitals have the same energy. That is,
they are degenerate, meaning energetically alike.
But when a uniformly spread
negative charge or a ligand approaches towards the d-orbitals of the metal
ions, then the electrostatic repulsion between d-electrons and this negative
charge would result in uniform increase in the energies of d-orbitals.
Though, under this condition the five d-orbitals of metal ions would still remain degenerate. Now consider that the negative charge or ligand surrounding d-orbitals of the metal ions gets concentrated in a number of point charges in certain specific positions.
The energy of the orbitals
lying in the directions of the point charges would be raised to a larger extent
than that of the orbitals lying in between the point charges.
Because of the electrons in the former type of
d-orbitals would experience greater repulsion from point charges than the
electrons in the later type of d-orbitals.
Consequently some of the
d-orbitals would get associated with a higher energy than the other d-orbitals
of the metal ions.
That is, the five
degenerate d-orbitals of the metal ions split up into two sets of orbitals.
They are d-orbitals of lower energy sets and d-orbitals of higher energy sets.
The splitting of the five
degenerate d-orbitals under the influence of negative charge or ligand is
called crystal field splitting.
Now the color of transition metal ions arises due
to excitation of electrons from the d-orbitals of lower energy to the
d-orbitals of higher energy which is called d-d transition or d-d excitation.
Now light radiations
corresponding to such small amounts of energy which are required for the above
mentioned d-d electron transitions, are available in the visible range.
This means that the
transition metals ions or transition metal compounds have the property to
absorb certain radiations from the visible region and exhibit the complementary
colors to that of the absorbed light.
For example, hydrated Cu
(II) ion absorbs radiations corresponding to the red light and transmits
radiation of wave lengths corresponding to the blue color which is the
complementary color of red color.
Again, anhydrous Co (II)
compounds also absorbs red light and therefore, appear blue. Similarly, the
hydrated Co (II) compounds absorb radiations of wave lengths corresponding to
blue color and hence appear red.
The transition metals ions
which have completely filled d-orbitals or have completely empty d-orbitals are
colorless.
Why Zn2+, Cd2+ and Hg2+ are colorless?
Zn2+, Cd2+
and Hg2+ are colorless. This fact can be explained on the basis of
their outer electronic configuration. The outer electronic configuration of Zn2+,
Cd2+ and Hg2+ are (n-1) d10.
That is, they have completely filled d-orbitals. Hence, in the case of Zn2+, Cd2+ and Hg2+, d-d transition does not occur. Therefore, no energy absorbed from visible range of light. So no color appeared.
Why Sc3+ and Ti4+ are colorless?
Sc3+ and Ti4+ are
colorless. This fact can be explained on the basis of their outer electronic
configuration. The outer electronic configuration of Sc3+ and Ti4+
are (n-1) d0.
That is, they have
completely vacant d-orbitals. Hence, in the case of Sc3+ and Ti4+,
d-d transition does not occur. Therefore, no energy absorbed from visible range
of light. So no color appeared.
What is d-d transition in co-ordination chemistry?
In the atom or ion of a
transition element, the transfer of electrons takes place from the lower energy
d-orbital to the higher energy d-orbital belonging to the same sub-shell. This
transfer requires a small amount of energy.
This transfer of electrons is usually accomplished by absorbing light rays of a specified frequency from visible light. This transfer of electrons is called d-d transition.
Note that the d-d transition
process cannot take place if the d-sub-shell has no electrons or if the
d-sub-shell is completely filled with electrons. As a result, the corresponding
ions as well as compounds become colorless.
- Why do transition metals form colored compounds?
- Why Zn2+, Cd2+ and Hg2+ are colorless?
- Why Sc3+ and Ti4+ are colorless?
- What is d-d transition in co-ordination chemistry?
transition
metals form colored compounds, Zn2+, Cd2+
and Hg2+ are colorless, Sc3+ and Ti4+ are
colorless, d-d transition in co-ordination chemistry,
No comments:
Post a Comment