Saturday, August 3, 2019

Why manganese does not form mono nuclear carbonyl compound but hydro derivative of such carbonyl is mono meric – explain ?

Why  manganese does not form mono nuclear carbonyl compound but hydro derivative of such carbonyl is monomeric – explain ?

The bonding in metal carbonyls can be explained with the help of valence bond theory . But the strength of  metal-carbonyl bond in carbonyl compounds can only be explained with the help of molecular orbital theory

Why  manganese does not form mono nuclear carbonyl compound but hydro derivative of such carbonyl is monomeric – explain ?

According to valence bond theory every element has the tendency to attain the next inert gas electronic configuration during compound formation .In carbonyls, also the transition metals are involved to attained the next inert electronic configuration.

 The atomic number of the next inert gas is termed as effective atomic number ( or EAN ). In all the metal carbonyl compounds , EAN rules is followed. Thus, the type of the metal carbonyl  either mono nuclear or poly nuclear , can be easily determined with the help of EAN rule

The numbers 36(Kr), 54(Xe), and 86 (Rn ) are the EAN of 3d, 4d and 5d series transition metal having even atomic number can be  easily form a mono nuclear carbonyl  compound .

Since CO  is a two electron  donar  so  EAN is attained easily. That is why  Ni ( CO )4  (28+2x4=36)   , Fe ( CO )5  (26+ 2x5=36 ) and  Cr(CO )6  (28+2x4=36 ) are known.
But Mn and Co can’t form a mono nuclear carbonyls compounds because they have odd atomic number and it is not possible to attain EAN  rules.

Why  manganese does not form mono nuclear carbonyl compound but hydro derivative of such carbonyl  is mono meric – explain ?

If one assumes that Mn ( CO )5  can be prepared then it would behave as a free radical [ 25+2x5 =35 , having one unpaired electron ] and will dimerise  easily . 

That is why manganese does not form mono nuclear carbonyl compound , but it forms the bimolecular carbonyl compounds like Mn2 (CO )10 which when reduced with hydrogen the hydro derivative HMn( CO ) is produced, it is very  stable because it obeys  EAN  rules .

   [ HMn( CO ) 5  ]  = ( 1+25 +2x5 ) =36  which is effective atomic  number . 

Practice problem:  

Why  manganese shows various oxidation states ?
What is effective atomic number (EAN) rules ? 

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