What is the shape and magnetic properties of Fe(CO)5?

 

The atomic number of iron is 26. The oxidation of state of Fe in Fe(CO)5 compound is zero. Now, the ligand CO is a very strong field ligand.

 

Hence due to influence of strong field CO ligand the four unpaired electron of 3d sub shell of Fe(0) becomes paired and two 4s electron is shifted to 3d sub shell.

 

As a result, 3d sub shell of Fe(0) occupied four paired electron in its four orbitals and the rest one orbital remain vacant.

 

This vacant 3d-orbital is mixed with one 4s and three 4p orbitals, resulting in the formation of five energetically equivalent dsp3 hybridized orbitals.

 

These vacant five hybridized orbitals accept five pair of electrons from five strong field CO ligand forming five co-ordinate bond, resulting in the formation tri-gonal bi-pyramidal  Fe(CO)5 molecule.

 

Since there is no unpaired electron in 3d-orbital of central metal Fe-atom, hence the resulting Fe(CO)5 compound shows diamagnetic properties.

 

However, the electronic configuration according to Hund’s rule the hybridization and shape of iron penta carbonyl compound is shown below.

 

 

 

• What is the shape and magnetic properties of Fe(CO)5?
• What is the geometry and magnetic properties of Fe(CO)5?
• Why Fe(CO)5 has tri-gonal bi-pyramid structure?
• What is the hybridization of Fe(CO)5?
• Why is Fe(CO)5 diamagnetic in nature?

Shape and magnetic properties of Fe(CO)5, geometry and magnetic properties of Fe(CO)5, hybridization of Fe(CO)5, Fe(CO)5 has tri-gonal bi-pyramid structure, Fe(CO)5 diamagnetic in nature,  

 

 

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