What is the geometry and magnetic properties of [Fe (H2O)6]2+ ion?
According
to valence bond theory, there are
two types of octahedral complexes are possible, namely, inner orbital complexes
and outer orbital complexes.
When
a transition or inner transition metals with a specific oxidation state forms
octahedral complexes, then some of complexes are inner orbital and some of
complexes are outer orbital.
Valence
bond theory explained this matter on the basis of hybridization of metal ion.Now,
in case of [Fe (H2O)6]2+ion, the oxidation
state of Fe atom is 2+ and co-ordination number of central metal Fe(II)ion ionis 6.
The
atomic number of Fe is 26 and that of ion (II) ion is 24. Hence, the valence
shell electronic configuration of Fe (II) ion is [Ar] d6.
Now,
according to valence bond theory, the electronic arrangement and hybridization
of [Fe (H2O)6]2+ion is shown below.
From
the above electronic configuration and hybridization of [Fe (H2O)6]2+ion,
it has been found that the central metal atom Fe utilizes outer 4d orbital for attaining the sp3d2 hybridization.
Hence,
the resulting complexes are called outer orbital complexes. In this case, the
3d orbital of Fe (II) metal ion remain unchanged.
Since,
in the formation of [Fe (H2O)6]2+ion, outer
orbital of Fe(II) metal ion is used hence it is also called high spin complex.
Now,
from the above electronic configuration it is find that the Fe (II) metal ion
have four unpaired electron in 3d-orbital and hence [Fe (H2O)6]2+ion
is paramagnetic.
What
is the geometry and magnetic properties of [Fe (H2O)6]2+
ion?
What
is the magnetic properties of [Fe (H2O)6]2+ ion?
Why
is [Fe (H2O)6]2+ ion paramagnetic ?
Calculate
the magnetic moment of [Fe (H2O)6]2+ ion.
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